$\,\,\because \,\,\,\frac{{\Sigma {x_i}}}{n}\,\, = \,\,\bar x$

$ \Rightarrow \,\,\,\frac{{a\,\, + \,\,b\,\, + \,\,8\,\, + \,\,5\,\, + \,\,10}}{5}\,\,\, = \,\,6\,\,$

$ \Rightarrow \,\,a\,\, + \,\,b\,\, = \,\,7\,\,…….\,\,(1)$

અને $\,\frac{{\Sigma x_i^2}}{n}\,\, – \,\,{{\bar x}^2}\,\, = \,\,{\sigma ^2}\,\,\,\,\,\,$

$ \Rightarrow \,\,\frac{{{a^2}\, + \,\,{b^2}\, + \,\,64\,\, + \,\,25\,\, + \,\,100}}{5}\,\, – \,\,36\,\, = \,\,6.8$

$ \Rightarrow \,\,{a^2}\, + \,\,{b^2}\, = \,\,25\,\,\,\,\,……..\,\,(2)$

સમીકરણ $(1)$  અને $(2) $ ને ઉકેલતા ${\text{a}}\,\, = \,\,{\text{4,}}\,\,{\text{b}}\,\, = \,\,{\text{3}}$ અથવા  $\,{\text{a}}\,\, = \,\,{\text{3,}}\,\,\,{\text{b}}\,\, = \,\,{\text{4}}$