English
Hindi
10-1.Circle and System of Circles
hard

$(6, -5) $ માંથી વર્તૂળ $ x^2 + y^2 - 2x + 4y + 3 = 0 $ પર દોરેલા સ્પર્શકોની જોડનું સમીકરણ....

A

$7x^2 + 23 y^2 + 30 xy + 66x + 50y - 73 = 0$

B

$7x^2 + 23y^2 - 30xy - 66x - 50 y + 73 = 0$

C

$7x^2 + 23y^2 + 30 xy - 66x - 50y - 73 = 0$

D

આપેલ પૈકી એકપણ નહી.

Solution

$SS_1 = T^2 ==> (x^2 + y^2 – 2x + 4y + 3) (36 + 25 – 12x – 20y + 3)= (6x – 5y – x – 6 + 2 (y – 5) + 3)^2 $

$==> 7x^2 + 23y^2 + 30xy + 66x + 50y – 73 = 0$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.