- Home
- Standard 11
- Mathematics
10-1.Circle and System of Circles
medium
જો વર્તૂળો $ x^2 + y^2 + 2x + 2ky + 6 = 0$ અને $ x^2 + y^2 + 2ky + k = 0 $ લંબરૂપે છેદે, તો $k = ..........$
A
$2 $ અથવા $-3/2$
B
$-2 $ અથવા $ -3/2$
C
$2 $ અથવા $3/2$
D
$-2$ અથવા $3/2$
Solution
$2g_1g_2 + 2f_1f_2 = c_1 + c_2$
$==> 2.1.0 + 2. k. k. = 6 + k$
અથવા $ 2k^2 – k – 6 = 0$
$==> (2k + 3) (k – 2) = 0$
$\therefore \,\,\,k\,\, = \,\,2\,,\,\, – \frac{3}{2}$
Standard 11
Mathematics
