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10-2. Parabola, Ellipse, Hyperbola
hard

વર્તૂળ $ x^2 + y^2 - 8x = 0 $ અને અતિવલય $\frac{{{x^2}}}{9}\,\, - \,\,\frac{{{y^2}}}{4}\,\, = \,\,1\,$બિંદુ $A $ અને $ B $ આગળ છેદે છે.  $AB $ વ્યાસવાળા વર્તૂળનું સમીકરણ......

A

$x^2 + y^2 - 12x + 24 = 0$

B

$x^2 + y^2 + 12x + 24 = 0$

C

$x^2 + y^2 + 24x - 12 = 0$

D

$x^2 + y^2 - 24x - 12 = 0$

Solution

$y\,\, = \,\, \pm \,\,2\sqrt 3 $

${\left( {x\,\, – \,\,6} \right)^2}\,\, + \;\,{y^2}\,\, – \,\,12\,\, = \,\,0$

${x^2}\,\, + \;\,{y^2}\, – \,\,12\,\,x\,\, + \;\,24\,\, = \,\,0$

$(a)$  અને $ (b) $ ઉકેલતાં  $, x$ માટે $x = 6$

 

Standard 11
Mathematics

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