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10-1.Circle and System of Circles
medium
જો $y = c$ એ વર્તૂળ $x^2 + y^2 -2x + 2y - 2 = 0$ નો $(1, 1)$ આગળનો સ્પર્શક હોય, તો $c$ નું મુલ્ય :
A
$1$
B
$2$
C
$-1$
D
$-2$
Solution
$y=c$ is tongent to the circle $x^2+y^2-2 x+2 y-2=0$ at $(1,1)$
To find the value of $c$.
The tangent $y=c$, the point $(1,1)$ is lies on $y=c$, then, $1=c$ Hence, the value of $c=1$
Standard 11
Mathematics
