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11.Thermodynamics
normal

$0.25\,{m^3}$ અચળ દબાણે વાયુનું કદ ${10^3}\,N/{m^2}$ વધારતાં થતું કાર્ય

A

$2.5$ ergs

B

$250 J$

C

$250 W$

D

$250 N$

Solution

$w = P \Delta V = {10^3} \times 0.25\, = 250\,J$

Standard 11
Physics

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