English
Gujarati
Basic of Logarithms
normal

$7\log \left( {\frac{{16}}{{15}}} \right) + 5\log \left( {\frac{{25}}{{24}}} \right) + 3\log \left( {\frac{{81}}{{80}}} \right)$ =

A

$0$

B

$1$

C

$\log 2$

D

$\log 3$

Solution

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Standard 11
Mathematics

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