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Basic of Logarithms
normal
$7\log \left( {\frac{{16}}{{15}}} \right) + 5\log \left( {\frac{{25}}{{24}}} \right) + 3\log \left( {\frac{{81}}{{80}}} \right)$ =
A
$0$
B
$1$
C
$\log 2$
D
$\log 3$
Solution
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Standard 11
Mathematics