In triangle $ABC$, the value of $\sin 2A + \sin 2B + \sin 2C$ is equal to
In triangle $ABC$, the value of $\sin 2A + \sin 2B + \sin 2C$ is equal to
- A
$4\sin A.\,\sin B.\,\sin C$
- B
$4\cos A.\,\cos B.\,\cos C$
- C
$2\cos A.\,\cos B.\,\cos C$
- D
$2\sin A.\,\sin B.\,\,\sin C$
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If $\sin \alpha = \frac{{ - 3}}{5},$ where $\pi < \alpha < \frac{{3\pi }}{2},$ then $\cos \frac{1}{2}\alpha = $
If $\sin \alpha = \frac{{ - 3}}{5},$ where $\pi < \alpha < \frac{{3\pi }}{2},$ then $\cos \frac{1}{2}\alpha = $
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$\frac{1}{{\sin 10^\circ }} - \frac{{\sqrt 3 }}{{\cos 10^\circ }} =$
- [IIT 1974]