600,pF નું એક કેપેસીટર 200,V સપ્લાય વડે વીજ ભ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$Q = CV =600 	imes 10^{-12} 	imes 200=12 	imes 10^{-8} C$

$	ext { Initial energy }=\frac{1}{2} CV ^2$

$=\frac{1}{2} 	imes 600 	imes 10^{-1

Vedclass · Accepted Answer

$6$

Vedclass · Answer

$Q = CV =600 	imes 10^{-12} 	imes 200=12 	imes 10^{-8} C$

$	ext { Initial energy }=\frac{1}{2} CV ^2$

$=\frac{1}{2} 	imes 600 	imes 10^{-12} 	imes(200)^2=12\,\mu J$

When connected to another uncharged capacitor

Charge will be equally distributed on identical capacitor

$Q ^{\prime}=\frac{ Q }{2}=6 	imes 10^{-8}$

Final energy $=2 	imes \frac{ Q ^{\prime 2}}{2 C }=\frac{ Q ^{\prime 2}}{ C }$

$\frac{\left(6 	imes 10^{-8}ight)^2}{600 	imes 10^{-12}}=6\,\mu J$

Energy lost = Initial energy - Final energy

$=(12-6)\,\mu\, J =6\, \mu\, J$

Similar Questions

$800$ માઈક્રો ફેરેડના કેપેસિટર પર $8 \times 10^{-18}\, C$ નો વિદ્યુતભાર મૂકવા કરવું પડતું કાર્ય ....