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5.Work, Energy, Power and Collision
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A block of mass m initially at rest is dropped from a height $h$ on to a spring of force constant $k$. the maximum compression in the spring is $x$ then
A$mgh = \frac{1}{2}k{x^2}$
B$mg(h + x) = \frac{1}{2}k{x^2}$
C$mgh = \frac{1}{2}k{(x + h)^2}$
D$mg(h + x) = \frac{1}{2}k{(x + h)^2}$
Solution
(b) Change in gravitational potential energy
$=$ Elastic potential energy stored in compressed spring
$ \Rightarrow mg(h + x) = \frac{1}{2}k{x^2}$
$=$ Elastic potential energy stored in compressed spring
$ \Rightarrow mg(h + x) = \frac{1}{2}k{x^2}$
Standard 11
Physics
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