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5.Work, Energy, Power and Collision
normal
A body of mass $2\, kg$ slides down a curved track which is quadrant of a circle of radius $1$ metre. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is .............. $\mathrm{m} / \mathrm{s}$

A
$4.43$
B
$2$
C
$0.5 $
D
$19.6$
Solution
(a) By conservation of energy, $mgh = \frac{1}{2}m{v^2}$
==> $v = \sqrt {2gh} = \sqrt {2 \times 9.8 \times 1} = \sqrt {19.6} = 4.43\;m/s$
Standard 11
Physics