Gujarati
5.Work, Energy, Power and Collision
normal

A body of mass $2\, kg$ slides down a curved track which is quadrant of a circle of radius $1$ metre. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is ..............  $\mathrm{m} / \mathrm{s}$

A

$4.43$

B

$2$

C

$0.5 $

D

$19.6$

Solution

(a) By conservation of energy, $mgh = \frac{1}{2}m{v^2}$

==> $v = \sqrt {2gh} = \sqrt {2 \times 9.8 \times 1} = \sqrt {19.6} = 4.43\;m/s$

Standard 11
Physics

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