A body travels uniformly a distance of (13.8 pm 0.2) m in a time (4.0 pm 0.3), s . velocity of body

English

Gujarati

Hindi

1.Units, Dimensions and Measurement

medium

A body travels uniformly a distance of $ (13.8 \pm 0.2) m$ in a time $(4.0 \pm 0.3)\, s$. The velocity of the body within error limits is

A

$(3.45 \pm 0.2) ms^{-1}$

B

$(3.45 \pm 0.3) ms^{-1}$

C

$(3.45 \pm 0.4) ms^{-1}$

D

$(3.45 \pm 0.5) ms^{-1}$

Solution

(b) Here, $S = (13.8 \pm 0.2)\,m$ and $t = (4.0 \pm 0.3)\,sec$

Expressing it in percentage error, we have,

$S = 13.8 \pm \frac{{0.2}}{{13.8}} \times 100\% = 13.8 \pm 1.4\% $

and $t = 4.0 \pm \frac{{0.3}}{4} \times 100\% = 4 \pm 7.5\% $

$ = \frac{{13.8 \pm 1.4}}{{4 \pm 7.5}} = (3.45 \pm 0.3)\;m/s.$

Standard 11

Physics

Share

Similar Questions

If $Q= \frac{X^n}{Y^m}$ and $\Delta X$ is absolute error in the measurement of $X,$ $\Delta Y$ is absolute error in the measurement of $Y,$ then absolute error $\Delta Q$ in $Q$ is

easy

The length of a cylinder is measured with a metre rod having least count $0.1 \;cm$. Its diameter is measured with vernier calipers having least count $0.01\; cm$. If the length and diameter of the cylinder are $5.0\; cm$ and $2.00\; cm$, respectively, then the percentage error in the calculated value of volume will be

medium

In the expression for time period $T$ of simple pendulum $T=2 \pi \sqrt{\frac{l}{g}}$, if the percentage error in time period $T$ and length $l$ are $2 \%$ and $2 \%$ respectively then percentage error in acceleration due to gravity $g$ is equal to ……… $\%$

medium

The temperature of a metal coin is increased by $100^{\circ} C$ and its diameter increases by $0.15 \%$. Its area increases by nearly

medium

(KVPY-2009)

A force $F$ is applied on a square area of side $L$. If the percentage error in the measurement of $L$ is $2 \%$ and that in $F$ is $4 \%$, what is the maximum percentage error in pressure is ………. $\%$

easy