A body travels uniformly a distance of (13.8 | vedclass

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Question

(b) Here, $S = (13.8 \pm 0.2)\,m$ and $t = (4.0 \pm 0.3)\,sec$

Expressing it in percentage error, we have,

$S = 13.8 \pm \frac{{0.2}}{{13.8}}

Vedclass · Accepted Answer

$(3.45 \pm 0.3) ms^{-1}$

Vedclass · Answer

(b) Here, $S = (13.8 \pm 0.2)\,m$ and $t = (4.0 \pm 0.3)\,sec$

Expressing it in percentage error, we have,

$S = 13.8 \pm \frac{{0.2}}{{13.8}} 	imes 100\% = 13.8 \pm 1.4\% $

and $t = 4.0 \pm \frac{{0.3}}{4} 	imes 100\% = 4 \pm 7.5\% $

$ = \frac{{13.8 \pm 1.4}}{{4 \pm 7.5}} = (3.45 \pm 0.3)\;m/s.$

A body travels uniformly a distance of $ (13.8 \pm 0.2) m$ in a time $(4.0 \pm 0.3)\, s$. The velocity of the body within error limits is

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