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1.Units, Dimensions and Measurement
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પદાર્થનું સ્થાનાંતર $(13.8 \pm 0.2) m$ અને લાગતો સમય $(4.0 \pm 0.3) s$ હોય,તો વેગ કેટલો થશે?
A
$(3.45 \pm 0.2) ms^{-1}$
B
$(3.45 \pm 0.3) ms^{-1}$
C
$(3.45 \pm 0.4) ms^{-1}$
D
$(3.45 \pm 0.5) ms^{-1}$
Solution
(b) Here, $S = (13.8 \pm 0.2)$m and $t = (4.0 \pm 0.3)\, sec$
Expressing it in percentage error, we have,
$S = 13.8 \pm \frac{{0.2}}{{13.8}} \times 100\% = 13.8 \pm 1.4\% $ and $t = 4.0 \pm \frac{{0.3}}{4} \times 100\% = 4 \pm 7.5\% $
$ = \frac{{13.8 \pm 1.4}}{{4 \pm 7.5}} = (3.45 \pm 0.3)\;m/s.$
Standard 11
Physics
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