A capacitor when filled with a dielectric $K = 3$ has charge ${Q_0}$, voltage ${V_0}$ and field ${E_0}$. If the dielectric is replaced with another one having $K = 9$ the new values of charge, voltage and field will be respectively
A capacitor when filled with a dielectric $K = 3$ has charge ${Q_0}$, voltage ${V_0}$ and field ${E_0}$. If the dielectric is replaced with another one having $K = 9$ the new values of charge, voltage and field will be respectively
- A
$3{Q_0},\;3{V_0},\;3{E_0}$
- B
${Q_0},\;3{V_0},\;3{E_0}$
- C
${Q_0},\;\frac{{{V_0}}}{3},\;3{E_0}$
- D
${Q_0},\;\frac{{{V_0}}}{3},\;\frac{{{E_0}}}{3}$
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