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14.Probability
easy
A card is drawn at random from a pack of cards. The probability of this card being a red or a queen is
A
$\frac{1}{{13}}$
B
$\frac{1}{{26}}$
C
$\frac{1}{2}$
D
$\frac{7}{{13}}$
Solution
(d) Required probability is
$P({\rm{Red}} + {\rm{Queen}}) – P({\rm{Red}} \cap {\rm{Queen}})$
$ = P({\rm{Red}}) + P({\rm{Queen}}) – 2P({\rm{Red}} \cap {\rm{Queen}})$
$ = \frac{{26}}{{52}} + \frac{4}{{52}} – \frac{2}{{52}} = \frac{{28}}{{52}} = \frac{7}{{13}}.$
Standard 11
Mathematics
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