A die is thrown, probability of following events: A number more than 6 will appear,

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14.Probability

easy

A die is thrown, find the probability of following events: A number more than $6$ will appear,

A

$0$

B

$0$

C

$0$

D

$0$

Solution

The sample space of the given experiment is given by

$S=\{1,2,3,4,5,6\}$

Let $D$ be the event of the occurrence of a number greater than $6.$

Accordingly, $D=\overset{\lower0.5em\hbox{$\smash{\scriptscriptstyle\frown}$}}{I}$

$\therefore P(D)=\frac{\text { Number of outcomes favourable to } D}{\text { Total number of possible outcomes }}=\frac{n(D)}{n(S)}=\frac{0}{6}=0$

Standard 11

Mathematics

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