10-2. Parabola, Ellipse, Hyperbola
hard

A hyperbola has its centre at the origin, passes through the point $(4, 2)$ and has transverse axis of length $4$ along the $x -$ axis. Then the eccentricity of the hyperbola is

A

$\frac {2}{\sqrt 3}$

B

$\frac {3}{2}$

C

$\sqrt 3$

D

$2$

(JEE MAIN-2019)

Solution

Given hyperbolo is

$\frac{{{x^2}}}{4} – \frac{{{y^2}}}{{{b^2}}} = 1$

Satisfying the point $\left( {4,2} \right)$

$ \Rightarrow {b^2} = \frac{4}{3}$

$ \Rightarrow e = \frac{2}{{\sqrt 3 }}$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.