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10-2. Parabola, Ellipse, Hyperbola
hard
A hyperbola has its centre at the origin, passes through the point $(4, 2)$ and has transverse axis of length $4$ along the $x -$ axis. Then the eccentricity of the hyperbola is
A
$\frac {2}{\sqrt 3}$
B
$\frac {3}{2}$
C
$\sqrt 3$
D
$2$
(JEE MAIN-2019)
Solution

Given hyperbolo is
$\frac{{{x^2}}}{4} – \frac{{{y^2}}}{{{b^2}}} = 1$
Satisfying the point $\left( {4,2} \right)$
$ \Rightarrow {b^2} = \frac{4}{3}$
$ \Rightarrow e = \frac{2}{{\sqrt 3 }}$
Standard 11
Mathematics