A pendulum suspended from the ceiling of a tr | vedclass

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Question

(b) Initially time period was $T = 2\pi \sqrt {\frac{l}{g}} $.
When train accelerates, the effective value of $g$ becomes $\sqrt {({g^2} + {a^2})} $

Vedclass · Accepted Answer

Decrease

Vedclass · Answer

(b) Initially time period was $T = 2\pi \sqrt {\frac{l}{g}} $.
When train accelerates, the effective value of $g$ becomes $\sqrt {({g^2} + {a^2})} $ which is greater than $g$
Hence, new time period, becomes less than the initial time period.

A pendulum suspended from the ceiling of a train has a period $T$, when the train is at rest. When the train is accelerating with a uniform acceleration a, the period of oscillation will

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