A quantity x is given by left( IF v^{2} / WL | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$x=\frac{I F V^{2}}{W L^{4}}$

$[ x ]=\frac{\left[ ML ^{2}\right]\left[ MI T ^{-2}\right]\left[ L T ^{-1}\right]^{2}}{\left[ ML ^{2} T ^{-2}\right][

Vedclass · Accepted Answer

Energy density

Vedclass · Answer

$x=\frac{I F V^{2}}{W L^{4}}$

$[ x ]=\frac{\left[ ML ^{2}\right]\left[ MI T ^{-2}\right]\left[ L T ^{-1}\right]^{2}}{\left[ ML ^{2} T ^{-2}\right][ L ]^{4}}$

$[ x ]=\left[ ML ^{-1} T ^{-2}\right]$

[Energy density] $=\left[\frac{ E }{ V }\right]$

$=\left[\frac{M L^{2} T^{-2}}{L^{3}}\right]$

$=\left[ ML ^{-1} T ^{-2}\right]$

Same as $x$

A quantity $x$ is given by $\left( IF v^{2} / WL ^{4}\right)$ in terms of moment of inertia $I,$ force $F$, velocity $v$, work $W$ and Length $L$. The dimensional formula for $x$ is same as that of

Similar Questions

If $A$ and $B$ are two physical quantities having different dimensions then which of the following can't denote a physical quantity?

if Energy is given by $U = \frac{{A\sqrt x }}{{{x^2} + B}},\,$, then dimensions of $AB$ is

If speed $V,$ area $A$ and force $F$ are chosen as fundamental units, then the dimension of Young's modulus will be :

Density of a liquid in $CGS$ system is $0.625 g/c{m^3}$. What is its magnitude in $SI $ system

The dimension of the ratio of magnetic flux and the resistance is equal to that of :