5.Work, Energy, Power and Collision
medium

એક $200\;g$ દળની ગોળી એક $4\; kg $ દળવાળી બંદૂકમાંથી છોડવામાં આવે છે, જેના વિસ્ફોટથી ઉદ્‍ભવતી ઊર્જા $1.05\; kJ $ છે. ગોળીનો પ્રારંભિક વેગ ($m/s$ માં) કેટલો હશે?

A

$40$

B

$120$

C

$100$

D

$80$

(AIPMT-2008)

Solution

$\begin{array}{l}
mv = Mv'\, \Rightarrow \,v' = \left( {\frac{m}{M}} \right)v\\
Total\,K.E.\,of\,the\,bullet\,and\,gun\\
\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{1}{2}m{v^2} + \frac{1}{2}M{v^2}\\
Total\,K.E. = \frac{1}{2}m{v^2} + \frac{1}{2}M.\frac{{{m^2}}}{{{M^2}}}{v^2}
\end{array}$

$\begin{array}{l}
Total\,K.E. = \frac{1}{2}m{v^2}\left\{ {1 + \frac{m}{M}} \right\}\\
 = \left\{ {\frac{1}{2} \times 0.2} \right\}\left\{ {1 + \frac{{0.2}}{4}} \right\}{v^2} = 1.05 \times 1000\,J\\
 \Rightarrow \,\,\,\,{v^2} = \frac{{4 \times 1.05 \times 1000}}{{0.1 \times 4.2}} = {100^2}\\
\therefore \,\,\,\,\,v = 100m{s^{ – 1}}
\end{array}$

Standard 11
Physics

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