A soap bubble assumes a spherical surface. Which of the following statement is wrong
A soap bubble assumes a spherical surface. Which of the following statement is wrong
- A
The soap film consists of two surface layers of molecules back to back
- B
The bubble encloses air inside it
- C
The pressure of air inside the bubble is less than the atmospheric pressure; that is why the atmospheric pressure has compressed it equally from all sides to give it a spherical shape
- D
Because of the elastic property of the film, it will tend to shrink to as small a surface area as possible for the volume it has enclosed
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Two bubbles $A$ and $B$ $(r_A > r_B)$ are joined through a narrow tube. Then
Two bubbles $A$ and $B$ $(r_A > r_B)$ are joined through a narrow tube. Then
A liquid column of height $0.04 \mathrm{~cm}$ balances excess pressure of soap bubble of certain radius. If density of liquid is $8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and surface tension of soap solution is $0.28 \mathrm{Nm}^{-1}$, then diameter of the soap bubble is . . . . . . .. . $\mathrm{cm}$.
$\text { (if } g=10 \mathrm{~ms}^{-2} \text { ) }$
A liquid column of height $0.04 \mathrm{~cm}$ balances excess pressure of soap bubble of certain radius. If density of liquid is $8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and surface tension of soap solution is $0.28 \mathrm{Nm}^{-1}$, then diameter of the soap bubble is . . . . . . .. . $\mathrm{cm}$.
$\text { (if } g=10 \mathrm{~ms}^{-2} \text { ) }$
- [JEE MAIN 2024]
The excess of pressure inside a soap bubble than that of the outer pressure is
The excess of pressure inside a soap bubble than that of the outer pressure is
Write the equation of excess pressure for liquid drop.
Write the equation of excess pressure for liquid drop.
The pressure inside a small air bubble of radius $0.1\, mm$ situated just below the surface of water will be equal to [Take surface tension of water $70 \times {10^{ - 3}}N{m^{ - 1}}$ and atmospheric pressure = $1.013 \times {10^5}N{m^{ - 2}}$]
The pressure inside a small air bubble of radius $0.1\, mm$ situated just below the surface of water will be equal to [Take surface tension of water $70 \times {10^{ - 3}}N{m^{ - 1}}$ and atmospheric pressure = $1.013 \times {10^5}N{m^{ - 2}}$]