13.Nuclei
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રેડિયો એક્ટિવ તત્વની એક્ટિવિટી $3$ દિવસ માં $(1/3)$ માં ભાગની થાય તો $9$ દિવસમાં એક્ટિવિટી.

A

$\frac{1}{27}$

B

$\frac{1}{9}$

C

$\frac{11}{8}$

D

$\frac{1}{3}$

(AIIMS-2009)

Solution

$R=R_{0} e^{-\lambda t}$

$\Rightarrow \frac{1}{3}=e^{-\lambda \times 3}=e^{-3 \lambda}$   ………$(1)$

Let activity in $9$ days be $R'$. Then

$\frac{R^{\prime}}{R_{0}}=e^{-\lambda \times 9}=e^{-9 \lambda} e^{-\lambda \times 3}=\left(e^{-3 \lambda}\right)^{3}$

$=\left(\frac{1}{3}\right)^{3}, \quad$    from $(1)$

$=\frac{1}{27} \Rightarrow R^{\prime}=\frac{R_{0}}{27}.$

Standard 12
Physics

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