Amplitude of left( {frac{{1 - i}}{{1 + i}}} r | vedclass

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Question

(a)$\left( {\frac{{1 - i}}{{1 + i}}} ight) = \frac{{1 - i}}{{1 + i}} 	imes \frac{{1 - i}}{{1 - i}} = \frac{{{{(1 - i)}^2}}}{2} = \frac{{ - 2i}}{2}

Vedclass · Accepted Answer

$-\pi\over2$

Vedclass · Answer

(a)$\left( {\frac{{1 - i}}{{1 + i}}} ight) = \frac{{1 - i}}{{1 + i}} 	imes \frac{{1 - i}}{{1 - i}} = \frac{{{{(1 - i)}^2}}}{2} = \frac{{ - 2i}}{2} = - i$
${\mathop{m Im}
olimits} (z) < 0$, Hence amplitude =$ - \pi /2$.

Amplitude of $\left( {\frac{{1 - i}}{{1 + i}}} \right)$ is

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