Decide, among the following sets, which sets are subsets of one and another:
$A = \{ x:x \in R$ and $x$ satisfy ${x^2} - 8x + 12 = 0 \} ,$
$B=\{2,4,6\}, C=\{2,4,6,8 \ldots\}, D=\{6\}$
$A = \{ x:x \in R$ and $x$ satisfy ${x^2} - 8x + 12 = 0\} $
$2$ and $6$ are the only solutions of $x^{2}-8 x+12=0.$
$\therefore A=\{2,6\}$
$B=\{2,4,6\}, C=\{2,4,6,8 \ldots\}, D=\{6\}$
$\therefore D \subset A \subset B \subset C$
Hence, $A \subset B, A \subset C, B \subset C, D \subset A, D \subset B, D \subset C$
In the following state whether $A=B$ or not :
$A=\{a, b, c, d\} ; B=\{d, c, b, a\}$
Which of the following sets are finite or infinite.
The set of positive integers greater than $100$
The number of elements in the set $\{x \in R :(|x|-3)|x+4|=6\}$ is equal to
Write the following sets in roster form :
$\mathrm{F} =$ The set of all letters in the word $\mathrm{BETTER}$
Consider the sets
$\phi, A=\{1,3\}, B=\{1,5,9\}, C=\{1,3,5,7,9\}$
Insert the symbol $\subset$ or $ \not\subset $ between each of the following pair of sets:
$A \ldots C$