1.Units, Dimensions and Measurement
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કઈ રાશિનું પારિમાણિક $M{L^2}{T^{ - 3}}$ થાય?

Aબળ 
Bપાવર 
Cઉર્જા 
Dકાર્ય

Solution

(b) Power $ = \frac{{{\rm{Work}}}}{{{\rm{Time}}}} = \frac{{M{L^2}{T^{ – 2}}}}{T} = M{L^2}{T^{ – 3}}$
Standard 11
Physics

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