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સમાન કદના ત્રણ એસિડ દ્રાવણની જેની $pH \,3, 4$ અને $5$ છે જે મિશ્રિત થાય છે.મિશ્રણમાં $H^+$ આયનની સાંદ્રતા .........$ \times 10^{-4} \,M$ હશે?
$37$
$11.1$
$1.11$
$3.7$
Solution
$\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right]$
-or $\quad\left[\mathrm{H}^{+}\right]=10^{-\mathrm{pH}} ;\left[\mathrm{H}^{+}\right]$ of solution $1=10^{-3}$
$\left[\mathrm{H}^{+}\right]$ of solution $2=10^{-4} ;\left[\mathrm{H}^{+}\right]$ of solution $3=10^{-5}$
Total concentration of $\left[\mathrm{H}^{+}\right]$
$=10^{-3}\left(1+1 \times 10^{-1}+1 \times 10^{-2}\right)$
$\Rightarrow 10^{-3}\left(\frac{1}{1}+\frac{1}{10}+\frac{1}{100}\right)$
$\Rightarrow 10^{-3}\left(\frac{100+10+1}{100}\right)$
$\Longrightarrow 10^{-3}\left(\frac{111}{100}\right)=1.11 \times 10^{-3}$
$So, \mathrm{H}^{+}$ ion concentration in mixture of equal volume of these acid solution $=1.11 \times 10^{-3} / 3=3.7 \times 10^{-4} \,\mathrm{M}$