Evaluate:

frac{sin 18^{circ}}{cos 72^{circ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}=\frac{\sin \left(90^{\circ}-72^{\circ}\right)}{\cos 72^{\circ}}$

$=\frac{\cos 72^{\circ}}{\cos 72^{\circ}}

Vedclass · Accepted Answer

$1$

Vedclass · Answer

$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}=\frac{\sin \left(90^{\circ}-72^{\circ}\right)}{\cos 72^{\circ}}$

$=\frac{\cos 72^{\circ}}{\cos 72^{\circ}}=1$

Evaluate:

$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}$

Similar Questions

Evaluate $\frac{\tan 65^{\circ}}{\cot 25^{\circ}}$

In $\triangle$ $ABC,$ right-angled at $B$, $AB =5\, cm$ and $\angle ACB =30^{\circ}$ (see $Fig.$). Determine the lengths of the sides $BC$ and $AC .$

Prove the following identities, where the angles involved are acute angles for which the expressions are defined.

$(\sin A+\operatorname{cosec} A)^{2}+(\cos A+\sec A)^{2}=7+\tan ^{2} A+\cot ^{2} A$

State whether the following are true or false. Justify your answer.

The value of $\sin \theta$ increases as $\theta$ increases.

$(\sec A+\tan A)(1-\sin A)=..........$

Evaluate: $\frac{\sin 18^{\circ}}{\cos 72^{\circ}}$