8. Introduction to Trigonometry
easy

કિંમત શોધો :

$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}$

A

$0$

B

$-1$

C

$1$

D

$10$

Solution

$\frac{\sin 18^{\circ}}{\cos 72^{\circ}}=\frac{\sin \left(90^{\circ}-72^{\circ}\right)}{\cos 72^{\circ}}$

$=\frac{\cos 72^{\circ}}{\cos 72^{\circ}}=1$

Standard 10
Mathematics

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