Find the $17^{\text {th }}$ and $24^{\text {th }}$ term in the following sequence whose $n^{\text {th }}$ term is $a_{n}=4 n-3$

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Substituting $n=17,$ we obtain

$a_{17}=4(17)-3=68-3=65$

Substituting $n=24,$ we obtain

$a_{24}=4(24)-3=96-3=93$

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