8. Sequences and Series
easy

જેનું $n$ મું પદ આપેલ છે તે શ્રેણીનાં ${a_9}$ પદ શોધો : $a_{n}=(-1)^{n-1} n^{3}$ 

A

$729$

B

$729$

C

$729$

D

$729$

Solution

Substituting $n=7,$ we obtain

$a_{9}=(-1)^{9-1}(9)^{3}=(9)^{3}=729$

Standard 11
Mathematics

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