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8. Sequences and Series
medium
Find the sum of odd integers from $1$ to $2001 .$
A
$1002001$
B
$1002001$
C
$1002001$
D
$1002001$
Solution
The odd integers from $1$ to $2001$ are $1,3,5 \ldots \ldots .1999,2001$
This sequence forms an $A.P.$
Here, first term, $a=1$
Common difference, $d=2$
Here, $a+(n-1) d=2001$
$\Rightarrow 1+(n-1)(2)=2001$
$\Rightarrow 2 n-2=2000$
$\Rightarrow n=1001$
$S_{n}=\frac{n}{2}[2 a+(n-1) d]$
$\therefore S_{n}=\frac{1001}{2}[2 \times 1+(1001-1) \times 2]$
$=\frac{1001}{2}[2+1000 \times 2]$
$=1001 \times 1001$
$=1002001$
Thus, the sum of odd numbers from $1$ to $2001$ is $1002001 .$
Standard 11
Mathematics
