If (b+c),(c+a),(a+b) are in H.P , then a^2,b^2,c^2 are in.......

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8. Sequences and Series

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If $(b+c),(c+a),(a+b)$ are in $H.P$ , then $a^2,b^2,c^2$ are in.......

A

$A.P.$

B

$G.P.$

C

$H.P.$

D

None

Solution

$(b+c)^{-1}, (c+a)^{-1}, (a+b)^{-1}$ are in $A.P$ so by using properties of $AP$ , we can show that $2b^2= a^2+b^2$

Standard 11

Mathematics

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