For any complex number z,bar z = left( {frac{1}{z}} right) if and only if

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4-1.Complex numbers

normal

For any complex number $z,\bar z = \left( {\frac{1}{z}} \right)$if and only if

A

$z$ is a pure real number

B

$|z| = 1$

C

$z$ is a pure imaginary number

D

$z = 1$

Solution

(b)Given that $\overline z = \frac{1}{z} \Rightarrow z\overline z = 1$ ==> $|z{|^2} = 1 \Rightarrow |z| = 1$
.

Standard 11

Mathematics

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