For any three positive real numbers $a,b,c$ ; $9\left( {25{a^2} + {b^2}} \right) + 25\left( {{c^2} - 3ac} \right) = 15b\left( {3a + c} \right)$ then

  • [JEE MAIN 2017]
  • A

    $a,b,c$ are in $G.P.$

  • B

    $b,c,a$ are in $G.P.$

  • C

    $b,c,a$ are in $A.P.$

  • D

    $a,b,c$ are in $A.P.$

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