For ellipse 3{x^2} + 4{y^2} = 12 , length of latus rectum is

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10-2. Parabola, Ellipse, Hyperbola

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For the ellipse $3{x^2} + 4{y^2} = 12$, the length of latus rectum is

A

$\frac{3}{2}$

B

$3$

C

$\frac{8}{3}$

D

$\sqrt {\frac{3}{2}} $

Solution

(b) $\frac{{{x^2}}}{4} + \frac{{{y^2}}}{3} = 1.$ Latus rectum $ = \frac{{2{b^2}}}{a} = 3$.

Standard 11

Mathematics

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