- Home
- Standard 11
- Mathematics
10-2. Parabola, Ellipse, Hyperbola
easy
For the ellipse $\frac{{{x^2}}}{{64}} + \frac{{{y^2}}}{{28}} = 1$, the eccentricity is
A
$\frac{3}{4}$
B
$\frac{4}{3}$
C
$\frac{2}{{\sqrt 7 }}$
D
$1\over3$
Solution
(a) ${e^2} = 1 – \frac{{{b^2}}}{{{a^2}}}$
${e^2} = \frac{{36}}{{64}}$
==> $e = \frac{3}{4}$.
Standard 11
Mathematics