Force F is given in terms of time t and distance x by F = a, sin, ct + b, cos, dx , then dimension o

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1.Units, Dimensions and Measurement

easy

Force $F$ is given in terms of time $t$ and distance $x$ by $F = a\, sin\, ct + b\, cos\, dx$, then the dimension of $a/b$ is

A

$[M^0L^0T^0]$

B

$[M^0L^1T^{-1}]$

C

$[M^0L^1T^0]$

D

$[M^1L^1T^{-2}]$

Solution

Dimension of $a =$ dimension of $b = [M^1L^1T^{-2}]$

Standard 11

Physics

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