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1.Units, Dimensions and Measurement
medium
To determine the Young's modulus of a wire, the formula is $Y = \frac{FL}{A\Delta L};$ where $L$ = length, $A = $area of cross-section of the wire, $\Delta L = $change in length of the wire when stretched with a force $F$. The conversion factor to change it from $CGS$ to $MKS$ system is .............. $10^{-1}\mathrm{N/m}^{2}$
A$100$
B$10$
C$1$
D$0.01$
Solution
(c) $Y = \frac{F}{A}.\frac{L}{{\Delta L}}$= $\frac{{dyne}}{{c{m^2}}} = \frac{{{{10}^{ – 5}}N}}{{{{10}^{ – 4}}{m^2}}} = 0.1N/{m^2}$
Standard 11
Physics
Similar Questions
Match List $I$ with List $II$ and select the correct answer using the codes given below the lists :
| List $I$ | List $II$ |
| $P.$ Boltzmann constant | $1.$ $\left[ ML ^2 T ^{-1}\right]$ |
| $Q.$ Coefficient of viscosity | $2.$ $\left[ ML ^{-1} T ^{-1}\right]$ |
| $R.$ Planck constant | $3.$ $\left[ MLT ^{-3} K ^{-1}\right]$ |
| $S.$ Thermal conductivity | $4.$ $\left[ ML ^2 T ^{-2} K ^{-1}\right]$ |
Codes: $ \quad \quad P \quad Q \quad R \quad S $
