- Home
- Standard 11
- Physics
1.Units, Dimensions and Measurement
medium
નીચે પૈકી કયું સૂત્ર પારિમાણિકની દ્રષ્ટિએ સાચું છે?
A$T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $
B$T = 2\pi \sqrt {\frac{{GM}}{{{R^3}}}} $
C$T = 2\pi \sqrt {\frac{{GM}}{{{R^2}}}} $
D$T = 2\pi \sqrt {\frac{{{R^2}}}{{GM}}} $
Solution
(a) By substituting the dimensions in $T = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}} $
we get $\sqrt {\frac{{{L^3}}}{{{M^{ – 1}}{L^3}{T^{ – 2}} \times M}}} = T$
we get $\sqrt {\frac{{{L^3}}}{{{M^{ – 1}}{L^3}{T^{ – 2}} \times M}}} = T$
Standard 11
Physics
