Function {sin ^{ - 1}}√ x is defined in interval

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1.Relation and Function

normal

Function ${\sin ^{ - 1}}\sqrt x $ is defined in the interval

A

$(-1, 1)$

B

$[0, 1]$

C

$[-1, 0]$

D

$(-1, 2)$

Solution

(b) Let $y = {\sin ^{ – 1}}\sqrt x \,\, \Rightarrow \,\,\sqrt x = \sin y$

$ \Rightarrow \,\,x = {\sin ^2}y,\,\,\,\,\therefore \,\,0 \le x \le 1$

Standard 12

Mathematics

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(JEE MAIN-2022)