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1.Relation and Function
normal
વિધેય ${\sin ^{ - 1}}\sqrt x $ એ .. . . અંતરાલમાં વ્યખ્યાયિત છે.
A
$(-1, 1)$
B
$[0, 1]$
C
$[-1, 0]$
D
$(-1, 2)$
Solution
(b) Let $y = {\sin ^{ – 1}}\sqrt x \,\, \Rightarrow \,\,\sqrt x = \sin y$
$ \Rightarrow \,\,x = {\sin ^2}y,\,\,\,\,\therefore \,\,0 \le x \le 1$
Standard 12
Mathematics
