Given the following two statements :
$\left( S _{1}\right):( q \vee p ) \rightarrow( p \leftrightarrow \sim q )$ is a tautology.
$\left( S _{2}\right): \sim q \wedge(\sim p \leftrightarrow q )$ is a fallacy.
Then
only $\left( S _{1}\right)$ is correct.
both $\left( S _{1}\right)$ and $\left( S _{2}\right)$ are correct.
both $\left( S _{1}\right)$ and $\left( S _{2}\right)$ are not correct.
only $\left( S _{2}\right)$ is correct.
$(p \to q) \leftrightarrow (q\ \vee \sim p)$ is
If $p \to ( \sim p\,\, \vee \, \sim q)$ is false, then the truth values of $p$ and $q$ are respectively .
Negation of "If India wins the match then India will reach in the final" is :-
Contrapositive of the statement:
'If a function $f$ is differentiable at $a$, then it is also continuous at $a$', is
If the Boolean expression $( p \Rightarrow q ) \Leftrightarrow( q *(\sim p ))$ is a tautology, then the Boolean expression $p *(\sim q )$ is equivalent to