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14.Probability
easy
Given two independent events $A$ and $B$ such that $P(A) $ $=0.3, \,P(B)=0.6$ Find $P(A$ and $B)$.
A
$0.18$
B
$0.18$
C
$0.18$
D
$0.18$
Solution
It is given that $P(A)=0.3,\,P(B)=0.6$..
Also, $A$ and $B$ are independent events.
$\mathrm{P}(\mathrm{A}$ and $\mathrm{B})=\mathrm{P}(\mathrm{A}) \cdot \mathrm{P}(\mathrm{B})$
$\Rightarrow $ $ \mathrm{P}(\mathrm{A} \cap \mathrm{B})=0.3 \times 0.6=0.18$
Standard 11
Mathematics