14.Probability
easy

Given two independent events $A$ and $B$ such that $P(A) $ $=0.3, \,P(B)=0.6$ Find $P(A$ and $B)$.

A

$0.18$

B

$0.18$

C

$0.18$

D

$0.18$

Solution

It is given that $P(A)=0.3,\,P(B)=0.6$..

Also, $A$ and $B$ are independent events.

$\mathrm{P}(\mathrm{A}$ and  $\mathrm{B})=\mathrm{P}(\mathrm{A}) \cdot \mathrm{P}(\mathrm{B})$

$\Rightarrow  $ $ \mathrm{P}(\mathrm{A} \cap \mathrm{B})=0.3 \times 0.6=0.18$

Standard 11
Mathematics

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