Given two independent events A and B such P(A)=0.3,,P(B)=0.6 . Find P( neither A or B)

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14.Probability

easy

Given two independent events $A$ and $B$ such $P(A)=0.3,\,P(B)=0.6 .$ Find $P($ neither $A$or $B)$

A

$0.28$

B

$0.28$

C

$0.28$

D

$0.28$

Solution

$P($ neither $A$ nor $B)$ $=P\left(A^{\prime} \cap B^{\prime}\right)$

$=\mathrm{P}\left((\mathrm{A} \cup \mathrm{B})^{\prime}\right)$

$=1-\mathrm{P}(\mathrm{A} \cup \mathrm{B})$

$=1-0.72$

$=0.28$

Standard 11

Mathematics

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