If $\alpha $ and $\beta $ are solutions of $sin^2\,x + a\, sin\, x + b = 0$ as well that of $cos^2\,x + c\, cos\, x + d = 0$ , then $sin\,(\alpha + \beta )$ is equal to
If $\alpha $ and $\beta $ are solutions of $sin^2\,x + a\, sin\, x + b = 0$ as well that of $cos^2\,x + c\, cos\, x + d = 0$ , then $sin\,(\alpha + \beta )$ is equal to
- A
$\frac{{2bd}}{{{b^2} + {d^2}}}$
- B
$\frac{{{a^2} + {c^2}}}{{2ac}}$
- C
$\frac{{{b^2} + {d^2}}}{{2bd}}$
- D
$\frac{{2ac}}{{{a^2} + {c^2}}}$
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