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यद् $A =\left[\begin{array}{ccc}\frac{2}{3} & 1 & \frac{5}{3} \\ 1 & 2 & 4 \\ 3 & 3 & 3 \\ \frac{7}{3} & 2 & \frac{2}{3}\end{array}\right]$ तथा $B =\left[\begin{array}{ccc}\frac{2}{5} & \frac{3}{5} & 1 \\ 1 & 2 & 4 \\ 5 & 5 & 5 \\ \frac{7}{5} & \frac{6}{5} & \frac{2}{5}\end{array}\right],$ तो $3 A -5 B$ परिकलित कीजिए
$\left[ {\begin{array}{*{20}{l}}
0&0&0 \\
0&0&0 \\
0&0&0
\end{array}} \right]$
$\left[ {\begin{array}{*{20}{l}}
0&0&0 \\
0&0&0 \\
0&0&0
\end{array}} \right]$
$\left[ {\begin{array}{*{20}{l}}
0&0&0 \\
0&0&0 \\
0&0&0
\end{array}} \right]$
$\left[ {\begin{array}{*{20}{l}}
0&0&0 \\
0&0&0 \\
0&0&0
\end{array}} \right]$
Solution
$3A – 5B = $ $3\left[ {\begin{array}{*{20}{l}}
{\frac{2}{3}}&1&{\frac{5}{3}} \\
{\frac{1}{3}}&{\frac{2}{3}}&{\frac{4}{3}} \\
{\frac{7}{3}}&2&{\frac{2}{3}}
\end{array}} \right]$ $ – 5\left[ {\begin{array}{*{20}{l}}
{\frac{2}{5}}&{\frac{3}{5}}&1 \\
{\frac{1}{5}}&{\frac{2}{5}}&{\frac{4}{5}} \\
{\frac{7}{5}}&{\frac{6}{5}}&{\frac{2}{5}}
\end{array}} \right]$
$ = \left[ {\begin{array}{*{20}{l}}
2&3&5 \\
1&2&4 \\
7&6&2
\end{array}} \right]$ $ – \left[ {\begin{array}{*{20}{l}}
2&3&5 \\
1&2&4 \\
7&6&2
\end{array}} \right]$
$ = \left[ {\begin{array}{*{20}{l}}
0&0&0 \\
0&0&0 \\
0&0&0
\end{array}} \right]$