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6.Permutation and Combination
easy
જો $^{n} C _{9}=\,\,^{n} C _{8}$ તો $^{n} C _{17}$ શોધો.
A
$1$
B
$1$
C
$1$
D
$1$
Solution
We have $^{n} C _{9}=\,^{n} C _{8}$
i.e., $\frac{n !}{9 !(n-9) !}=\frac{n !}{(n-8) ! 8 !}$
or $\frac{1}{9}=\frac{1}{n-8}$ or $n-8=9$ or $n=17$
Therefore $^{n} C_{17}=\,^{17} C_{17}=1$
Standard 11
Mathematics