If $P$ and $Q$ are two statements, then which of the following compound statement is a tautology?
$(( P \Rightarrow Q ) \wedge \sim Q ) \Rightarrow Q$
$(( P \Rightarrow Q ) \wedge \sim Q ) \Rightarrow \sim P$
$(( P \Rightarrow Q ) \wedge \sim Q ) \Rightarrow P$
$(( P \Rightarrow Q ) \wedge \sim Q ) \Rightarrow( P \wedge Q )$
$\left( {p \wedge \sim q \wedge \sim r} \right) \vee \left( { \sim p \wedge q \wedge \sim r} \right) \vee \left( { \sim p \wedge \sim q \wedge r} \right)$ is equivalent to-
The compound statement $(\sim( P \wedge Q )) \vee((\sim P ) \wedge Q ) \Rightarrow((\sim P ) \wedge(\sim Q ))$ is equivalent to
$( S 1)( p \Rightarrow q ) \vee( p \wedge(\sim q ))$ is a tautology $( S 2)((\sim p ) \Rightarrow(\sim q )) \wedge((\sim p ) \vee q )$ is a Contradiction. Then
The number of ordered triplets of the truth values of $p, q$ and $r$ such that the truth value of the statement $(p \vee q) \wedge(p \vee r) \Rightarrow(q \vee r)$ is True, is equal to
Statement $\quad(P \Rightarrow Q) \wedge(R \Rightarrow Q)$ is logically equivalent to