If $1+\left(2+{ }^{49} C _{1}+{ }^{49} C _{2}+\ldots .+{ }^{49} C _{49}\right)\left({ }^{50} C _{2}+{ }^{50} C _{4}+\right.$ $\ldots . .+{ }^{50} C _{ so }$ ) is equal to $2^{ n } . m$, where $m$ is odd, then $n$ $+m$ is equal to.

  • [JEE MAIN 2022]
  • A

    $98$

  • B

    $97$

  • C

    $96$

  • D

    $99$

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  • [JEE MAIN 2019]

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