7.Binomial Theorem
hard

यदि $1+\left(2+{ }^{49} C _1+{ }^{49} C _2+\ldots \ldots+{ }^{49} C _{49}\right)\left({ }^{50} C _2+\right.$ $\left.{ }^{50} C _4+\ldots . .+{ }^{50} C _{50}\right)=2^{ n } . m$ है, जहाँ $m$ एक विषम संख्या है, तो $n + m$ बराबर है $..........$

A

$98$

B

$97$

C

$96$

D

$99$

(JEE MAIN-2022)

Solution

$1+\left(1+2^{49}\right)\left(2^{49}-1\right)=2^{98}$

$m=1, n=98$

$m + n =99$

Standard 11
Mathematics

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